Translations:Documentation/Calc Functions/BITAND/18/en

From The Document Foundation Wiki
Jump to: navigation, search
Formula Description Returns
=BITAND(6;10) 6 in binary is 0110 and 10 in binary is 1010 so
(0110 & 1010 = 0010)
2 (0010)
=BITAND(123;156) 123 in binary is 01111011 and 156 in binary is 10011100 so
(01111011 & 10011100)
24 (00011000)
=BITAND(6.123;10) floor value of 6.123 is taken so 6 in binary is 0110 and 10 in binary is 1010 so
(0110 & 1010 = 0010)
2 (0010)
=BITAND(123; 2^48 + 5) number 2 argument is greater than 2^48 hence it will return an error Err:502
=BITAND(123; -5) number 2 argument is negative hence it will return an error Err:502