Translations:Documentation/Calc Functions/BITAND/18/en

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    Formula Description Returns
    =BITAND(6;10) 6 in binary is 0110 and 10 in binary is 1010 so
    (0110 & 1010 = 0010)
    2 (0010)
    =BITAND(123;156) 123 in binary is 01111011 and 156 in binary is 10011100 so
    (01111011 & 10011100)
    24 (00011000)
    =BITAND(6.123;10) floor value of 6.123 is taken so 6 in binary is 0110 and 10 in binary is 1010 so
    (0110 & 1010 = 0010)
    2 (0010)
    =BITAND(123; 2^48 + 5) number 2 argument is greater than 2^48 hence it will return an error Err:502
    =BITAND(123; -5) number 2 argument is negative hence it will return an error Err:502