Translations:Documentation/Calc Functions/BITOR/18/en

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    Formula Description Returns
    =BITOR(6;10) 6 in binary is 0110 and 10 in binary is 1010 so
    (0110 | 1010 = 1110)
    14 (1110 or E)
    =BITOR(6.123;10) floor value of 6.123 is taken so 6 in binary is 0110 and 10 in binary is 1010 so
    (0110 | 1010 = 1110)
    14 (1110 or E)
    =BITOR(123;156) 123 in binary is 01111011 and 156 in binary is 10011100 so
    (01111011 | 10011100 = 11111111)
    255 (11111111)
    =BITOR(123; 2^48 + 5) number 2 argument is greater than 2^48 hence it will return an error Err:502
    =BITOR(123; -5) number 2 argument is negative hence it will return an error Err:502