Translations:Faq/Math/005/7/en

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    [math]\displaystyle{ \begin{align} 3(x+4)-2(x-1) &= 3 x+12-(2 x-2) \\ &= 3 x+12-2 x+2 \\ &= x+14 \end{align} }[/math] ""3(x+4)-2(x-1)=3 x+12-(2 x-2) newline
    ""phantom {3(x+4)-2(x-1)}=3 x+12-2 x+2 newline
    ""phantom {3(x+4)-2(x-1)}=x+14