# Documentation/Calc Functions/BITOR

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BITOR

Mathematical

## Summary:

Returns a bitwise logical "or" of the parameters. If any one of the values or both the values at a given position is/are 1 in the binary representation of the parameter numbers then the output is 1 at that position. Note: This functions is available since LibreOfficeDev 3.5.

## Syntax:

BITOR(Number 1; Number 2)

## Returns:

Returns a positive integer.

## Arguments:

Number 1 and Number 2 are positive integers less than 2 ^ 48 (281,474,976,710,656).

• If either argument is a decimal number then its floor value is considered.
• If either argument is less than 0, BITOR returns the Err:502.
• If either argument is a non-integer or is greater than (2^48)-1, BITOR returns the Err:502.

None

## Examples:

Formula Description Returns
=BITOR(6;10) 6 in binary is 0110 and 10 in binary is 1010 so
`(0110 | 1010 = 1110)`
14 (1110 or E)
=BITOR(6.123;10) floor value of 6.123 is taken so 6 in binary is 0110 and 10 in binary is 1010 so
`(0110 | 1010 = 1110)`
14 (1110 or E)
=BITOR(123;156) 123 in binary is 01111011 and 156 in binary is 10011100 so
`(01111011 | 10011100 = 11111111)`
255 (11111111)
=BITOR(123; 2^48 + 5) number 2 argument is greater than 2^48 hence it will return an error Err:502
=BITOR(123; -5) number 2 argument is negative hence it will return an error Err:502 BITOR example showing that if either number have 1 at a position then the function returns 1 at that position.

OR

BITAND

BITXOR

## ODF standard:

Section 6.6.4, part 2

BITOR